
Annie L.
asked 04/01/24PERMUTATIONS HELP: How can you arrange 9 people if Tina has to be next to Quinton OR Tatiana?
The answer is 151,200 but I am not getting that
2 Answers By Expert Tutors

Iordan G. answered 05/01/24
Mathematics PhD with expertise in data science & statistical learning
The problem is an application of the inclusion-exclusion principle.
The permutations where Tina and Quinton are next to each other are 2*8!. Indeed, the 8! is form considering Tina and Quinton as a unit, and the 2 is from the two possible orders: Tina then Quinton versus Quinton then Tina.
Similarly, the permutations where Tina and Tatiana are next to each other are also 2*8!.
Now we need to exclude the permutations where Tina is next to both Quinton and Tatiana. Those are 2*7! since we consider all three to be a unit, and we can arrange the triple as Quinton, Tina, and Tatiana, or as Tatiana, Tina, and Quinton.
So, by the inclusion-exclusion principle, the final answer is 2*8! + 2*8! - 2*7! = 151200.

Mark M. answered 04/02/24
Mathematics Teacher - NCLB Highly Qualified
Consider the two as a unit
Tina and Quinton (in that order) x 7!
Quintin and Tina (in that order) x 7!
Tina and Tatiana (in that order) x 7!
Tatiana and Tina (in that order) x 7!
Is the sum of those 151,200?
Annie L.
I am not sure what the math would be for "Tina and Quinton (in that order)", but here is what I originally did Tina and Quinton being together: 8! x 2! = 80640 Tina and Tatiana being together: 8! x 2! = 80640. Then, 80640 + 80640 = 161280 so that was wrong.04/02/24
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Mark M.
Is Tina in the middle or are the three just in a group?04/02/24