What is the magnitude of the induced emf (in V) in the loop 1.00 s after it begins to move?

Question

Can anyone help me with letter D? I keep getting the wrong answer. Here's the link to the picture of the full question. https://ibb.co/7WymLCZ

Answer 1

To determine the magnitude of the induced electromotive force (emf) in the loop 1.00 second after it begins to move, we need to consider Faraday's law of electromagnetic induction. Faraday's law states that the induced emf in a loop is equal to the rate of change of magnetic flux through the loop.

Mathematically, Faraday's law is expressed as:

\[ \text{emf} = -N \frac{\Delta \Phi}{\Delta t} \]

where:

- \(\text{emf}\) is the induced electromotive force (emf) in volts (V),

- \(N\) is the number of turns in the loop,

- \(\Delta \Phi\) is the change in magnetic flux in webers (Wb),

- \(\Delta t\) is the time interval in seconds (s).

Given that the loop begins to move and assuming this movement causes a change in magnetic flux, we can calculate the emf using the above formula.

However, the specific values for \(N\), \(\Delta \Phi\), and \(\Delta t\) are not provided in your question. To calculate the induced emf, we need information about the number of turns in the loop, the rate of change of magnetic flux, and the time interval over which this change occurs.

If you have the necessary values, please provide them so that I can help you calculate the induced emf. Alternatively, if you're looking for a general explanation of how to calculate induced emf using Faraday's law, I can provide that as well.