Raymond B. answered 02/06/24
Math, microeconomics or criminal justice
f(x) = sqr((x+1)/(x-1))
g(x) = lnx
domain of f(x) is all real numbers except those that make the denominator =0 or make the square root imaginary, which is x=1 and (x+1)/(x-1)<0, x<-1
or in interval notation x is not in the interval (-infinity, -1)U{1}
x is in the intervals [-1,1)U(1,infinity)
range of f(x) is [0, infinity) or x>/=0
domain of g(x) is x>0 or x is in the interval (0, infinity)
range of g(x) is all real numbers
f(g(x)) = f(lnx) = sqr((lnx+1)/(lnx-1))
g(f(x)) =g(sqr((x+1)/(x-1))) = ln(sqr((x+1)/(x-1)))
domain of f(g(x)) is the interval (0, infinity), when x>0, same as the domain of g(x)
domain of g(f(x)) = almost the same as domain of f(x), but f(x) can't = 0
which is the interval (-1,1)U(1,infinity)
it may help to use a graphing calculator on the functions
Josh D.
so the domain for f(x) is it (-1,1)U(1,infinity), I had (-infinity, 1)U(1,infinity)02/06/24