midterm help-Calculus help, urgent

Question

Solve the following inequality. Express the exact answer in interval notation, restricting your attention to −𝜋 ≤ x ≤ 𝜋.

sin2(x) < 3/4

Answer 1

sin^2(x)<3/4

take square roots of both sides

sqr-3/2 < sinx < sqr3/2

arcsin(sqr-3/2) < x < arcsin(sqr3/2)

where x is between negative pi and positive pi radians

-60<x < 60 or

-pi/3<x<pi/3

120<x<180 and -180<x<-120 or

2pi/3< x< pi and -pi<x<-2pi/3

x is in 3 intervals (2pi/3,pi), (-pi,-2pi/3), (-pi/3,pi/3)

or in degrees (120,180), (-180,-120), (-60,60)