
Mark M. answered 12/20/23
Mathematics Teacher - NCLB Highly Qualified
The first derivative of each provides the slope of each. If the slopes are negative reciprocal the lines are orthogonal.
Berlin V.
asked 12/20/23How do you check orthogonality condition for these curves, I know only the answer that they are but I can't seem to move forward with the solution. I appreciate your help.
Mark M. answered 12/20/23
Mathematics Teacher - NCLB Highly Qualified
The first derivative of each provides the slope of each. If the slopes are negative reciprocal the lines are orthogonal.
Dayv O. answered 12/22/23
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
this is what I see
u(x,y)=x2-y2
v(x,y)=2xy
u+iv=z2,,,,where z=x+iy
z2 is differentiable (meets du/dx=dv/dy) implying the intersection of u(x,y)=k and v(x,y)=k
is orthogonal.
to prove for this specific complex variable function
find x when u(x,y)=v(x,y)
and x when ux=-1/vx
for both 4x4-4kx2-k2=0
If ∫ x*y = 0, then the functions are orthogonal.
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