Find the critical numbers of the function. (Enter your answers as a comma-separated list.)

Question

Answer 1

Critical points occur where the derivative of g(t) = 0.

The derivative of √(5 – t) = –1/[2√(5 – t)]

1. Use this and the product rule to find the derivative g'(t) = t√(5 – t)
2. Set g'(t) = 0
3. Solve for t

Hope this helps. If you have any questions (or get stuck) just add a comment.

(Hint: the critical point is a number between 3 and 4.)