Rachel M.

asked • 09/03/23

Here are the positions at thtree different times for a bee in flight

time one: 6.1 s position 1 (-2.9, 9.7,0)

time two: 6.5 s position two {-0.8, 6.7, 0)

A) between 6.1 and 6.5 what was the bee's average velocity

average velocity = (5.25, -7.5, 0) (assignment counted that as correct)

D) using the best information available what was the displacement of the bee during the time interval from 6.1 to 6.13s

I'm using the position prediction formula which is

r final = r initial + v average * delta time

rf = (-2.9, 9.7,0) + (5.25, -7.5, 0) * 0.03

my answer was (-2.7425, 9.475, 0) it was counted practically correct because zero is he only correct number

what am I doing wrong?

1 Expert Answer

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Dayv O. answered • 09/03/23

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Rachel M.

well you can't add displacement of 6.13 to initial 6.1 if you don't know 6.13
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09/03/23

Dayv O.

(5.25, -7.5, 0) * 0.03 is a displacement, displaced from a point can be computed, but the displacement itself is .03*5.25 is x direction, .03*-7.5 in y direction, and 0 in z direction.
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09/03/23

Dayv O.

from time 6.1 to 6.13, the displacement itself is (5.25, -7.5, 0) * 0.03, I agree with your r when t=6.13 equation and answer.,,, How about if we wanted displacement estimate only for time 6.25 to 6.28, then displacement estimate is (5.25, -7.5, 0) * 0.03 given average velocity=(5.25, -7.5, 0) from t=6.1 to t=6.5. To compute the estimate of r at t=6.28 would need r at t=6.25
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09/03/23

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