A) Find the impulse given to the block. B) What momentum is required by the block? C) Find the final velocity of the block.

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PLEASE PROVIDE THE COMPLETE ANSWER. THIS IS FOR MY ACTIVITY IN SCHOOL :)

A 4-kg block at rest is acted upon by a constant force of 45 N for 6.6 s. A) Find the impulse given to the block. B) What momentum is required by the block? C) Find the final velocity of the block.

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Answer 1

Hi Elle,

Impulse= FΔt or mΔv which is also Δmomentum=m(vf-vi)

Momentum=mv

where, here, m=4kg

F=45N

Δt=6.6 sec

vi=0 (initially at rest)

(a) Impulse=45*6.6=297 N-s

(c) Let: 297=4(vf-0)→ vf=74.25 m/s

For part (b), I's say it's either m*vf (which would yield 297 kg-m/s, considering it started from rest). *It could also even mean the average momentum which would be 4(.5)(74.25)=148.5 kg-m/s

I'm leaning more towards the first case however.

I hope this helps!