Raymond B. answered 06/13/23
Math, microeconomics or criminal justice
25C8 = 25!/8!(25-8)! = 25!/8!17!
= 25(24)(23)(22)(21)(20)(19)(18)/8(7)(6)(5)(4)(3)(2)
= about 1.086 x 10^6
unless order matters, then you want 25P8 which is much larger =
25!/17!
= about 4.361 x 10^10
but the problem as given uses the word "combinations"
some small calculators have nCr and nPr keys which calculate the combinations and permutations for you
in this example n=25, r = 8
your solution is even larger than 25P17