Whats dy/dx of x squared minus the square root of 2 times x times y plus 3 times y squared equals 23?

Answer 1

d/dx [ x² - √2xy + 3y² = 23 ]

2x - √2(y + x dy/dx) + 6y dy/dx = 0

(-√2x + 6y) dy/dx = -2x + √2y

dy/dx = (-2x + √2y) / (-√2x + 6y)