How to find g′(1) if g of x is equal to 5 times x cubed minus 6 times x squared plus 8 times x plus the square root of 8 period

Answer 1

Given g(x) = 5x^3-6x²+8x+sqrt(8)

To find the derivative g'(x) we take note of the following

if f(x) = ax^b-c; the derivative is obtained by multiplying the x exponent with the x coefficient and then subtracting the coefficient by one. The derivative of a constant is 0.

f'(x) = abx^(b-1)

g(x) = 5x^3-6x²+8x+sqrt(8)

g'(x) = 5•3x² - 6•2x +8

g'(x)= 15x²- 12x +8