Sebastien B. answered 09/25/24
Math, Physics, Chemistry - Experienced Credentialed Tutor/Teacher.
a) We use the units of the international system: MKSA, i.e. m, kg, s, A, mol, K, Cd.
Optical fiber connection: electromagnetic wave speed c = 200,000 km/s (because the optical fiber is made of glass). Distance between Bobcaygeon (Ontario) and Miami (USA) d = 2,500 km, so the round trip is 2d = 5,000 km.
Satellite connection: electromagnetic wave speed c' = 300,000 km/s (in air). Distance covered by the waves between Bobcaygeon, the satellite, Miami d' = 2,550 km (with Pythagorus), so the round trip is 2d' = 5,100 km.
b) Fiber optic connection:
We use the formula c = D/t with c = 200,000 km/s and D = 2d = 5,000 km.
Thus: t = 2d/c = 5,000/200,000 = 0.025 s = 25 ms.
Satellite connection:
We use the formula c' = D'/t' with c' = 300,000 km/s and D' = 2d' = 5,100 km.
Thus: t' = 2d'/c' = 5,100/300,000 = 0.017 s = 17 ms.
We therefore prefer the operator who offers satellite connection, which is 1/3 faster.
Note: Although faster, the satellite connection is more sensitive to interference and external disturbances, as it is not “wired” like the fiber optic connection.