Can someone help me with this math calculation problem please

Question

Sean's exam grades:

Exam 1- 74.29%

Exam 2- 71.43%

Exam 3- 65.71%

Exam 4- 65.71%

** Exams are worth 75% of Sean's grade, weighing the lowest score 50% relative to the other three

Sean's Discussion grade is 97.25%, which is 25% of his grade.

Question: What is Sean's total grade calculation (in percentage)?

Note: **Please don't forget to weigh the lowest exam score 50% relative to the other three which are weighted 75%

Answer 1

Sam's Grade: = (Dissection grade)•(25%) + (Exam Grade)•(75%)

Dissection is weighted at 25%

The exam grades are weighted where the lowest score will only count as 50% compared with the other test scores. (Sometimes the lowest grade is dropped completely. From your question it sounds like the lowest grade only counts 50% towards the total exam percentage). With that assumption then.

If all the exams were weighted the same, then you would add the total points scored and divide by the total points possible).

But since the exams are not equally weighted.

exam grade weight total

1 74.29% 1 74.29%

2 71.43% 1 71.43%

3 65.71% 1 65.71%

4 65.71% 0.5 32.86%

So the exam average would be (74.29%+71.43%+65.71%+32.86%)/(1+1+1+0.5)= 69.80%

The final grade would then be

(Dissection grade)•(25%) + (Exam Grade)•(75%)

(97.25%)(25%) + (69.80%)(75%) = 76.66%

Answer 2

4.29 + 1.43- 4.29-4.29 = 5.72 - 7.58 = -1.86

calculating the difference of each exam grade and 70

-.1.8646=- .46, average of exams = 70-.46 = 69.54%= average exam score

it has weight of 75%

25% of the final grade is 97.25

(3(69.98) + 97.25)/4 = the Final Grade

=210-.06 +97.25)/4 = 307.85/4= 76.57%

the lowest exam score is a tie between exams 3 and 4

they already essentially count as 50% of the 75%