MALANA L.
asked • 05/05/23the length of a rectangle is 5 times its width. If the perimeter is 60 what is the area?
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2 Answers By Expert Tutors
Raymond B. answered • 05/05/23
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L=5w
P=60=2(L+w)
30=L+w
30= 5w+w
6w=30
w= 30/6= 5
L= 5(5)= 25
A=Lw=25(5)= 125
Robert K. answered • 05/05/23
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Let X = width(W)
5X = length(L)
P = 2L+ 2W
60 = 2(5X) + 2X
60 = 10X + 2X
60 = 12X
X = 5
Width = 5
Length = 25
A= LW
A = (25)(5)
A = 125
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Patrick F.
First, write down the length in terms of the width as an equation. Then, write down an equation for the perimeter, using only one variable (width would be natural). Solve for the width then use your first equation to solve for the length. Now you have what you need for the area.05/05/23