If j(x) = f(x3), what would j′(−1), plz explain.

Question

Answer 1

Assuming that the graph is f(x)

j(x) = f(x³)

By the Chain Rule, j'(x) = f'(x³)(3x²)

So, j'(-1) = 3f'(-1) = 3(2) = 6

Answer 2

If the graph is f(x), then from -4 to 0 the graph is y = 2x -2. The graph has a slope of 2: for every two over, it goes 4 up. 4/2 = 2.

The y intercept is -2, where it crosses the y axis.

The equation at x=-1 is y = 2x - 2 = f(x)

f(x^3) = 2x^3 - 2 (replace x with x^3) = j(x)

j'(x) = 6x^2

j'(-1) = 6*(-1)^2 = 6