
Anthony T. answered 04/21/23
Patient Science Tutor
Using the equation given, let H(t) =0, then 0 = -16t^2 + 32t. Solve this equation for t.
t (-16 t + 32) = 0.
The are two solutions: t = 0 and t = 2 sec. It takes 2 seconds to reach the ground.
A check on this is to use the relation Vfinal = Vinitial - gt, where Vfinal = 0 at the top of the trajectory. Solve for t = -32 ft/s / -32 ft /s^2 = 1 sec. As the time up equals the time down, the total time is 2 seconds as determined above.