Bradford T. answered 04/03/23
Retired Engineer / Upper level math instructor
Let x be the width of each column of the row and y be the height.
+---+---+---+---+---+
| | | | | | y
+---+---+---+---+---+
x x x x x
Total fence:
10x + 6y = 650
y = (650-10x)/6
Area, A= 5xy
A(x) = (5/6)x(650-10x) = (5/6)(650x-10x2)
A'(x) = (5/6)(650-20x)
Set to zero and solve for x
x = 65/2 = 32.5 feet
y = (650-325)/6 = 325/6 ≈ 54.167 feet
Total width of the row = 5(32.5) = 162.5 feet