HELP!! I NEED HELP WITH THIS QUESTION!! What is the vertex of the parabola with the equation y = x2 + 10x - 3?

Question

What is the vertex of the parabola with the equation y = x2 + 10x - 3?

Answer 1

The fastest way to find the vertex of an quadratic equation in the general from of:

f(x) = ax² + bx +c

is to use the following formula:

x = -b/2a

In this case:

x = -(10)/(2)(1) = -5

Plugging this onto the equation yields:

f(-5) = (-5)² + 10(-5) - 3

f(-5) = 25 - 50 - 3

f(-5) = -28

The vertex is: (-5, -28)

The vertex in this case is at the lowest point of the graph and the -28 represents the minimum value of the function.

Answer 2

y = x² + 10x + 25 - 3 - 25, complete the square

y = (x + 5)² - 28, vertex form

(-5, -28)