Maria B. answered 03/13/23
Maria12345678910
We are given the formula for the altitude of the projectile as a function of time:
s = -16t2 + v0 t+s0
where v0 is the initial velocity and s0 is the initial height.
In this case, v0 = 272 ft/sec and s0 = 0 ft (since the projectile is launched from ground level).
We want to find when the projectile's height above ground is less than or equal to 480 ft. In other words, we want to find when s <= 480.
Substituting the values of v0 and s0, we get:
s = -16t^2 + 272t
Now we can set up the inequality:
-16t^2 + 272t <= 480
Simplifying and dividing both sides by -16 (remembering to flip the inequality since we are dividing by a negative number), we get:
t^2 - 17t + 30 >= 0
Now we can factor the quadratic expression:
(t - 2)(t - 15) >= 0
This inequality is true when either both factors are non-negative (i.e. t <= 2 or t >= 15), or both factors are negative (i.e. 2 <= t <= 15).
So the projectile's height above ground will be less than or equal to 480 ft either immediately after launch (when t = 0) or during the time interval [2 sec, 15 sec].
Egeg G.
In interval notation.03/12/23