Inactive Tutor answered 02/22/23
Let x be the width and y be the length.
2x+y = 32 m
xy =128 m2
y = 128/x
2x+128/x = 32
2x2-32x +128 = 0
x2-16x+64=0
(x-8)(x-8) = 0
x=8 meters = Width
y = 128/8 = 16 meters = Length
Vincent P.
asked 02/22/23A farmer needs to enclose three sides of a meadow with a fence (the fourth side is a cliff wall). The farmer has 32 meters of fence and wants the meadow to have an area of 128 sq-meters. What should the dimensions of the meadow be? (For the purpose of this problem, the width will be the smaller dimension (needing two sides); the length with be the longer dimension (needing one side). Additionally, the length should be as long as possible.)
length = _____ meters
width = _____ meters
Enter your answers as numbers. If necessary, round to the nearest hundredths.
Inactive Tutor answered 02/22/23
Let x be the width and y be the length.
2x+y = 32 m
xy =128 m2
y = 128/x
2x+128/x = 32
2x2-32x +128 = 0
x2-16x+64=0
(x-8)(x-8) = 0
x=8 meters = Width
y = 128/8 = 16 meters = Length
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