the length of a rectangular garden is four times its width. the garden has a perimeter of 280 feet. write and solve a system to determine the dimensions of the garden.

Question

A system : 2 equations using either substitution or elimination! THANK YOU!

Answer 1

L=4w

2L+2w = 280

L+w = 140

4w +w = 140

5w = 140

w= 140/5

w =28 feet wide

L = 140-28= 112 feet long

2(28+112)

=2(140)

=280 feet perimeter

Answer 2

Hello, thank you for taking the time to post your question!

The starting point here is to take the idea that length is four times the width and that the perimeter, meaning 2L + 2W, is equal to 280. So that gives us our system of equations:

L = 4W

2L + 2W = 280

Substituting L = 4W into the second equation gives

2(4W) + 2W = 280

10W = 280

W = 28

Then you can plug that back into the first equation to find the length

L = 4W = 4(28) = 112

I hope that helps get you moving in the right direction! Feel free to reach out if you have any additional questions beyond that :)