Raymond B. answered 08/15/21
Math, microeconomics or criminal justice
j = 2,2, 7, 1/3
k= 1/4, 4, 5, 2/3
1/3k + 4/3j =1/6 +16/3=33/6= 11/2 when (j,k) = (2,1/4)
but maybe you meant (1/3)k + (4/3)j? then it = 2/3 +1/3=1 when (j,k) = (2,1/4)
when (j,k) =(2,4) then 1/3k+4/3j = 1/6+1/3= 1/2
but (1/3)k+ (4/3)j = 2/3+16/3 = 18/3 = 6
when (j,k) = (7,5) 1/3k+4/3j = 1/21 + 4/15 = 33/105 = 11/37
and (1/3)k+(4/3)j = 7/3+20/3 = 27/3 = 9
(j,k)= (1/3, 2/3)
1/3k+4/3j = 1 +2 = 3
(1/3)k + (4/3)j = 1/9 +8/9 = 1