
Yefim S. answered 02/12/23
Math Tutor with Experience
T1 = 2π√m/k; T2 = 2π√(m + 1)/k; T1/T2 = √m/(m+ 1); m /(m + 1) = f22/f12 = 1/4; 4m = m + 1; 3m = 1; m = 1/3 kg
VIVEK A.
asked 02/12/23The natural frequency of a spring-mass system is found to be 2 Hz. When an additional
mass of 1 kg is added to the original mass m, the natural frequency is reduced to 1 Hz. Find
the spring constant k and the mass m.
Yefim S. answered 02/12/23
Math Tutor with Experience
T1 = 2π√m/k; T2 = 2π√(m + 1)/k; T1/T2 = √m/(m+ 1); m /(m + 1) = f22/f12 = 1/4; 4m = m + 1; 3m = 1; m = 1/3 kg
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