the cost of 12 oranges and 7 apples is $5.36. 8 oranges and 5 apples cost $3.68. find the cost of each

Answer 1

Let x = cost of one orange and y = cost of one apple

12x + 7y = 5.36

8x + 5y = 3.68

Multiply the first equation by 2 and the second by -3 to get:

24x + 14y = 10.72

-24x - 15y = -11.04

Add the equations to solve for y. Then solve for x.

Answer 2

Let O be the cost of a single orange and A be the cost of a single apple.

Thus 12*O+7*A=5.36 and 8*O+5*A=3.68, two equations and both must be true.

Re-arrange the first one to find O= (5.36-7*A)/12

Substitute the above into the second equation to get 8*(5.36-7A)/12+5*A=3.68.

Simply to find A= $...32

Substitute the value of A into either equation to find O. Using the first one we get 12*O+7*.68=5.36. Solve now and find O= $.26