Sheryl R. answered 01/16/23
North Fulton Summer Sessions for Middle School, Algebra, Geometry
Another way to look at it is to set up a formula with one variable.
Let n = number of nickels
n+4 = number of dimes
4(n+4) = number of quarters
Write an equation to multiply each expression with the value of the coin to get the total, x
x = (.05)n + (.10)(n+4) + (.25)(4)(n+4)
Multiply and distribute to simplify terms
x = .05n + .10n + .40 + n + 4
Combine like terms
x = 1.15n + 4.40
Since you have a range between 10 and 11, try the max for 11 as the value for x
11 = 1.15n + 4.40
Subtract 4.40 from each side
11-4.40 = 1.15n + 4.40-4.40
6.6 = 1.15n
Divide both sides by 1.15 to get number of nickels
6.6 ÷ 1.15 ≈ 5.74≈ n
Since you can’t have a fraction of a coin and it can’t be more than 11, round down to 5 and calculate the totals:
5 nickels = .25
5+4 dimes = 9 dimes = .90
4(9) quarters = 36 quarters = 9.00
.25 + .90 + 9.00 = 10.15