The picture shown below has a uniform frame-width of 3/4 inches. What is the approximate area, in square inches, of the viewable portion of the picture?

Question

The picture shown below has a uniform frame-width of 3/4 inches. What is the approximate area, in square inches, of the viewable portion of the picture?

Answer 1

Hi Saja,

You can see that the width = 20 and length = 32. You are further told that the uniform-width is uw = 3/4 = 0.75.

You have for width: 20 = uw+ viewable width + uw = viewable width + 1.5 and thus:

viewable width = 20 -1.5

You also have for length: 32 = uw + viewable length + uw = viewable length + 1.5 and thus:

viewable length = 32-1.5

The area of the viewable portion is thus, as for any rectangle : (20 -1.5) * (32-1.5), which is what Mark wrote.

Answer 2

(32 - 1.5)(20 - 1.5)