As it's given that the relationship between study time and items recalled, the equation will be in the slope-intercept form: y = mx + b
Let's say that study time runs on the x-axis and items recalled is on the y-axis.
Slope = rise/run = (y2 - y1)/(x2 - x1) (0.40 - 0.31)/(8 - 5) = 0.09/3 = 0.03 (m)
Use one of pairs to determine (b)
0.31 = 0.03(5) + b → 0.31 = 0.15 + b
b = 0.16
y = 0.03x + 0.16
For 10 sec y = 0.03(10) + 0.16 = 0.3 + 0.16 = 0.46 items
Take this function with a little skepticism. For 0 seconds, they'd remember 0.16 of the items!!
Robert J.
Just quick math... The change from 5 seconds to 8 seconds was about 30%. So, each added second would add 10% (.03). 10 seconds would be an additional 20% (.06). The answer is the same as yours, .46 items but just another way that allows you to do it in your head!12/26/22