
Carlos Miguel M.
asked 11/25/22differential calculus (pls help) rush
Determine the coefficients a, b, c, etc. so that the curve will satisfy the stipulated condition.
make the curve y = ax^4+bx^3+cx^2+dx+e pass though the points (1, 9) and have critical points at (0, 0) and (-1, -1).
1 Expert Answer

Yefim S. answered 11/25/22
Math Tutor with Experience
y(0) = e = 0; y(- 1) = a - b + c - d = -1; y(1) = a + b + c + d = 9; y'(x) = 4ax3 + 3bx2 + 2cx + d;
y'(0) = d = 0; y'(- 1) = - 4a + 3b - 2c = 0; 2a + 2c = 8; a + c = 4; 2b = 10; b = 5;
4a + 2c = 15; 2a = 7; a = 7/2; c = 1/2
y = 7/2x4 + 5x3 + 1/2x2
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Doug C.
Substitute the coordinates of the points (1,9),(0,0),(-1,-1) into the function definition to get 3 equations with 5 unknowns. Substitute the x-coordinates of (0,0) and (-1,-1) into the first derivative setting the result equal to zero (critical numbers). Now you have 5 equations and 5 unknowns. Solve the system. You will quickly realize that e = 0 and d=0, so really 3 equations with 3 unknowns.11/25/22