dsin(θn) = nλ are the bright fringes on one side of the central spotbright fringe. The answer will be 2n+1 if n is the number of bright fringes to one side of the central bright spot.
We are not solving for all possible bright spots which would entail solving for the largest n so that θ is the greatest angle less than 90°.
In this case we must use the equation yn = Ltanθn (Normally the equation nλ/d = yn/L is only used for the first or 2nd fringe (small θ)) L is distance to the screen.
Process:
1) θn = tan-1(screen width/2 /L) (Remember it's one-sided analysis)
2) n = (d/λ)sin(θn) (Note d = (1/530) mm and λ = 540 nm → put both in meters)
3) Truncate n to next integer value. Answer is 2n+1
Please consider a tutor. Take care.