Determine the HLB of a mixture of 45 grams of Span 80 (HLB 4.3) and 105 grams of polysorbate 80 (HLB 15).

Answer 1

Span 80 fraction of total = 45/150 = 0.3

Polysorbate fraction of total = 105/150 = 0.7

HLB of mixture = (0.3 x 4.3) + (0.7 x 15)

= 1.29 + 10.5 = 11.79