Write an equations in Slope-Intercept Form that passes through (-6,-3) and (6,-7).

Answer 1

You first need to find the slope of the line that passes through the two points

m = (y₂ - y_{1) /} ( x₂ - x₁) = (-3 - -7)/(-6 - 6) =4/-12 = -1/3 Becareful with the signs

Use this slope with either point and the point-slope form. y - y₁ = m(x - x₁)

Using the point (-6, -3) y - -3 = -1/3( x - -6) simplify

y + 3 = -1/3( x +6) multiply by 3

3y + 9 = - x - 6

3y = - x - 15

y = (-1/3)x - (5)