Given a situation that x can be any number between 4 and 30 that is divisible by 3, what value of x can be added to the data set 4, 8, 10, 20, and 30 to get a mean of 15? explai

Answer 1

x=18

(4+8+10+20+30+x) =6(15)= 90

x = 90-4-8-10-20-30=90-72 = 18

4<18<30

and

18/3 = 4, dividing evenly by 3

mean= arithmetic average = sum of the data, divided by the number of data 90/6 =15

average without x is (4+8+10+20+30)/5 = 72/5 = 14.4

to bring the average up from 14.4 to 15 requires a number larger than 15, which is exactly 18