Given P(x) = x^3 - 3x^2 + 16x - 48, find the EXACT Zeros of P by factoring: The Zeros are: 3, 4i, -4i.

Question

Given P(x) = x^3 - 3x^2 + 16x - 48, find the EXACT Zeros of P by factoring:

The Zeros are: 3, 4i, -4i.

Write P in factored form (as a product of linear factors). Be sure to write the full equation, including P(x)=.

P(x)=_______________________

Answer 1

P(x) = (x-3)(x-4i)(x+4i)

= (x-3)(x^2+16)

= x^3 -3x^2 +16x -48