For the function N(y)=4|3y−8|−4, evaluate N(y)+N(1).

Answer 1

In this case this question is asking for a formula expression. This question reads evaluate N(y)+N(1). Plug in what N(y)+N(1) equals. N(y)=4|3y-8|-4. Where there is N(y) substitute 4|3y-8|-4 for N(y). Note: N(1) means to take the number 1 and substitute whenever there is a y. So, when it's plugged in, it becomes 4|3y-8|-4+4|3(1)-8|-4.

4|3y-8|-4+4|3(1)-8|-4

I used distributive property , adding like terms and order of operations to get the answer

It becomes 12y-32-4+4|(3-8)|-4

>12y-36+4|-5|-4

>12y-36+4(5)-4

>12y-36+20-4

>rewriting and putting like signs tog

12y-36+-4+20

>12y-40+20

>12y-20

Answer 12y-20