Determine whether each ordered pair is a solution to the inequality y<x−3.

Question

(-9,-3)

(4,-10)

(5,4)

(2,3)

(-5,5)

Ps.

when I did my work while waiting I got the first solution as false along with the third and last one of the solutions and the ones I got true were the second and fourth solution but I have a feeling I am wrong. I have an IEP and have a tendency to second guess myself on my math work

Answer 1

Hello Bailey, my advice if you feel doubtful about this kind of inequality problems would be to resort to a number line, which can be specially useful when we deal with negative numbers, as in the first case (-9;-3):

1. (-9;-3)

y<x-3

-3<-9-3

-3<-12 False

1. (4;-10)

y<x-3

-10<4-3

-10<-1 True

1. (5;4)

y<x-3

4<5-3

4<2 False

1. (2;3)

y<x-3

3<2-3

3<-1 False

1. (-5;5)

y<x-3

5<-5-3

5<-8 False

Answer 2

The fourth one is FALSE.

x-3 = 2-3 = -1

y = 3 > -1