sample size (n) = (z alpha/2 * s/E)^2
z alpha/2 = z for 0.995 probability = 2.58
s = 19.5
E = 3
plug values into sample size (n) equation and compute
Decrease in confidence reduces sample size required because z alpha/2 is 1.645
Brandon A.
asked 09/28/22A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 3 points with 99% confidence assuming s=19.5 based on earlier studies? Suppose the doctor would be content with 90% confidence. How does the decrease in confidence affect the sample size required?
A 99% confidence level requires __?___ subjects. (Round to the nearest subject)
sample size (n) = (z alpha/2 * s/E)^2
z alpha/2 = z for 0.995 probability = 2.58
s = 19.5
E = 3
plug values into sample size (n) equation and compute
Decrease in confidence reduces sample size required because z alpha/2 is 1.645
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