Yefim S. answered • 09/21/22
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∑1nk(k + 1)(k + 2) = ∑1n(k3 + 3k2 + 2k) = n2(n + 1)2/4 + n(n + 1)(2n + 1)/2 + n(n + 1)
Alisa T.
asked • 09/21/22Compute: 1*2*3+2*3*4+…+n*(n+1)*(n+2)
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