a metallurgust has one allot containing 26% aluminum and another containing 37% aluminum. How many pounds of each alloy must he use to make 53 pounds of a third alloy containing 31% aluminum

Question

find the pounds of alloy containing 27% aluminum

find the pounds of alloy containing 37% aluminum

Answer 1

(x lbs)(26%) + (53-x lbs)(37%) = (53 lbs)(31%)

26x + 1961 - 37x = 1643

11x = 318

x = 28.9 lbs = 29 lbs of 26%

24 lbs of 37%