A 40.0 m water silo with a diameter of 8.2m is checked weekly to determine when it will need to be filled.

Question

If the level of water changes from 22.4 m to 20.8m, how many pounds of water was used that week? The temperature of the water is 23.3F resulting in a density of 0.9975 gmL^-1

Volume of the silo (cylinder) is V=(pie)r^2(h)

28.35 g = 10z

1lb =16oz

Report in scientific notation (sig figs)

Answer 1

First, let's figure out the volume of the water that has been used:

V = (πD²/4) x (22.4 - 20.8) = (3.14159 x 8.2 x 8.2)/4 x 1.6 = 84.496 m³

Let's convert this volume to mass in kilograms:

Mass = V x density = 84.496 m³ x 0.9975 kg/m³ = 84.285 kg

Let's convert it to pounds:

1. 84.285 kg * 1000 g/kg = 84285 g - total grams
2. Oz = 84285/28.35 = 2973.015 oz - number of ounces in 84285 grams
3. Lbs = Oz/16 = 2973.015/16 = 185.813 lbs - weight in pounds