The general term appears to be xn+1/(5n+1ln (n+1))
The ratio of the n+2 term to the n+1 term converges to x/5 (and you should prove that!).
With that information you should be able to answer the question.
Eric B.
asked 09/05/22What is the ratio of convergence and interval of convergence of f in a power series like:
f(x) = (x^(2) / 5^(2)ln2) - (x^(3) / 5^(3)ln3) + (x^(4) / 5^(4)ln4) - (x^(5) / 5^(5)ln5) + ...
The general term appears to be xn+1/(5n+1ln (n+1))
The ratio of the n+2 term to the n+1 term converges to x/5 (and you should prove that!).
With that information you should be able to answer the question.
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