There are two attractive forces being applied to B in opposite directions. The upward force has magnitude
k(10-9)(2·10-9)/0.0162
(Notice that I have converted nC to coulombs, and cm to meters. k is Coulomb's constant, roughly 8.99x109 in SI units.)
and the downward force has magnitude
k(2·10-9)(2·10-9)/0.0062
If we subtract these quantities and compute them, we get a downward net force of about 9.3·10-4. Your answer is almost correct, but is missing a negative sign to indicate the downward direction.
It makes sense that the net force be downward anyway; charge C is both stronger and closer than charge A.