n = 0.25 * (1.645/0.03)^2 = 751.67 ~ 752
Ashley P.
asked 07/28/2290% Confidence Interval for True Population Proportion
Suppose a mobile phone company wants to determine the current percentage of customers aged 50+ who use text messaging on their cell phones. How many customers aged 50+ should the company survey in order to be 90% confident that the estimated (sample) proportion is within three percentage points of the true population proportion of customers aged 50+ who use text messaging on their cell phones.
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