Raymond B. answered 07/27/22
Math, microeconomics or criminal justice
f(x) = (1/2)x +1
g(x) = 3x-1
f(g(x)) = f(3x-1) = (1/2)(3x-1)+1 = 3x/2 -1/2 +1 = 3x/2 + 1/2
the domain of x is any real number
UNLESS you
meant f(x) = 1/(2x) +1
then
f(g(x)) = 1/(2(3x-1) +1 = 1/(6x-2) + 1 = (1+6x-2)/(6x-2) = (6x-1)/(6x-2)
an the domain of x is any real number except x=1/3. as it makes the denominator =0 and the expression undefined
you've written the latter way, so it would likely be the correct answer
but people on line often intend it the 1st way, so it's almost a toss up which way to go