In general, a vector is ai + bj. To find the angle, If theta is the reference angle, tan theta = b/a.
theta = arctan (b/a)
The magnitude will be sqrt(a^2 + b^2).
u iarctan(3/3) = arctan(1) = 45 degrees.
Magnitude = sqet(9+0) = sqrt(18) = sqrt(2*9) = 3*sqrt(2). You could also get this by knowing the side length ratios of a 45 45 90 triangle. The sides opposite the 45 degree angles are x, and the side opposite the 90 degree angle is x*sqrt(2).
v arctan(4/3) = 53.13 degrees
Magnitude = sqrt(16+9) = sqrt(25) = 5. You may also recognize it as a special right triangle: 3,4,5
