
Jon S. answered 07/12/22
Patient and Knowledgeable Math and English Tutor
Help with the 1st question:
probability of getting 2 defective units: 3 C 2 * 10 C 1 / 13 C 3 (where n C r is number of combinations of n taken r at a time)
probability of getting 3 defective units: 3 C 3 * 10 C 0 / 13 C 3
add to get total probability of getting at least 2 defective units