Laila H.

asked • 07/10/22

I need help with this problem I'm getting the wrong answers when doing the quadratic formula

Keq = 3.143x10-5 for the reaction below:

NH2CH2COOH(aq) + C2H5OH(aq) <--> NH2CH2COOC2H5(aq) + H2O(l)


So if you were to combine 5.171g of NH2CH2COOH and 8.167g of C2H5OH in

enough water to make 160.00mL of the solution, what are the equilibrium concentrations of all reactants and products?

J.R. S.

tutor
I just spent 15 minutes answering this and then it didn't show up. From the quadratic I got x = 1.549 M and x = 0.3078 M. You would use 0.3078 since 1.549 is greater than starting concentrations. Sorry the answer didn't post but I don't want to spend another 15 minutes showing the workings. Good luck.
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07/10/22

J.R. S.

tutor
For equilibrium concentrations, I got the following: [NH2CH2COOH] = 0.1227 M [C2H5OH] = 0.8002 M [NH2CH2COOC2H5] = 0.3078 M
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07/10/22

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