
Ryan C. answered 07/08/22
Ivy League Professor | 10+ Years Experience | Patient & Kind
Hi Jonothan,
Thanks for your question!
First, for simplicity, I'm going to redefine my variables. Let's let A = -x and B = 2y. Then, our binomial power is just (A+B)12. I'd like to expand out this new expression and find the term that contains B9. According to the binomial theorem, this term will be 12C9 A3B9, where nCk = n! / (k! (n-k)!).
Now I'm going to plug back in my original variables into this term, so that 12C9 A3B9 becomes 12C9 (-x)3(2y)9 or, simplifying, -1*12C9 *29x3y9. Thus, the coefficient of the term that contains y9 for the original binomial power is -1*12C9 *29 = -112640. This is the final answer.