What is the mole fraction of water in this solution?

Question

You have prepared a solution by dissolving 25.559g of glucose (C6H12O6) in 60.0mL of water. What is the mole fraction of water in this solution? And the mole fraction of glucose in this solution as well

Answer 1

No. of moles of glucose = 25.559/180 ​= 0.14199

No. of moles of water = 60/18 ​= 3.333

Mole fraction of glucose = 0.14199/(3.333+0.14199) ​= 0.14199/3.47499 = 0.04086

Mole fraction of water = 3.333/(3.333​+0.14199) = 3.333/3.47499 = 0.9591