Raymond B. answered 07/01/22
Math, microeconomics or criminal justice
distance divided by time = speed
d/t = s
97.81 minutes = 97.81/60 hours = about 1.63 hours total time
d/t
=total distance divided by total time
=7.63/(97.81/60)
= about 4.68 mph
which is probably the answer you want
(yet it doesn't use the additional information in the problem, breaking down the time into walk and run times)
SO maybe , "whole walk"isn't referring to the entire distance, just the "walk parts" and "whole walk" is different from "entire walk" which includes the "run part"?
then 97.81-18.89-73.75= 97.81-92.64= 5.17 minutes running
73.75/60 hrs. at 3.93 mph
5.17/60 hr. at run speed
18.89/60 hr. at 2.79 mph
find the run distance, then
find run speed and then find the weighted average speed
total distance 7.63 miles
d=st
1st walk distance = 3.93(73.75/60) = about 4.83 miles
2nd walk distance = 2.79(18.89/60) = about 0.88 miles
4.83+0.88= 5.71 miles so, the run part = 7.63-5.71 =1.92 miles
run distance = 7.63 - 3.93(73.75/60) - 2.79(18.89/60) = 1.92 miles
then run speed = d/t = 1.92/(5.17/60) = about 22.3 mph
use a weighted average of 3.93, 2.79, and 22.3 mph
Go with 4.68 mph as it is greater than 3.93 and 2.79, reflecting a faster positive run speed in between
take a weighted average of speeds, weighted by time at each speed
22.3(5.7) + 3.93(73.75) + 2.79(18.89)
= 457.8231
divide by total time 97.81
457.8231/97.81
= 4.68 mph = average speed
same as just dividing total distance by total time = 7.63/(97.81/60) = 4.68 mph