Help me solve this problem

Question

The specific heat of solid aluminum metal at 273.15K and 1 bar pressure is 0.897 J/g*K. When 27.49kJ of heat is added to a block of Al(s), the temperature rises from 280.9K to 337.3K. What is the mass (in g) of the aluminum block? Show your steps

Answer 1

You should use the formula

Q = m C ΔT, where

Q is heat (27.49 kJ = 27,490 J)

m is mass (?)

C is specific heat (0.897 J g^-1 K^-1)

and

ΔT is temperature change (337.3 K - 280.9 K = 56.4 K)

Solving for m and substituting the known quantities we get

m = Q / (C ΔT) = 27,490 / (0.897 x 56.4) g = 543 g